Talk:Experience

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Revision as of 19:21, 9 January 2010 by Naokohiro (talk | contribs) (Mentioned lack of information on how experience is spread throughout multiple participants in battle.)
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Erratic (600000) E = -1/50*l^4 + 2*l^3 for level<=50

http://www.math.miami.edu/~jam/azure/forum/tuff/ultimatebb.php?ubb=get_topic;f=1;t=001260

It's mentioned in the thread that level 45 does not work for that. Level 45 is 100273, not 100237. Sheep 16:42, 21 Feb 2005 (UTC)

Nevermind the previous message, I figured it out myself. Sheep 18:09, 21 Feb 2005 (UTC)

Experience gain in battle

The section on the experience gained in battle only mentions the total experience gained, and not how experience is spread throughout multiple participants in the battle. That information seems like a useful mechanic and should be appended by someone who can add it. --Naokohiro 19:21, 9 January 2010 (UTC)

Simplify the formulas

Was that copied from matlab or something? It can be simplified...

((0.814 - 0.02*(((n - 69) / 3) - (((n - 69) / 3) modulo 1)) - ep(((n - 69) modulo 3))(n^3)

((0.814 - 0.02*(((n - 69) / 3) - float_part((n - 69) / 3) ) - ep(((n - 69) modulo 3))(n^3)
((0.814 - 0.02*( int((n - 69) / 3) ) - ep(((n - 69) modulo 3))(n^3)
((0.814 - 0.02*( int(n/3 - 23) ) - ep(((n - 69) modulo 3))(n^3)
((0.814 + 0.46 - 0.02*( int(n/3) ) - ep(((n - 69) modulo 3))(n^3)

int(  (  1.274 - 0.02*(int(n/3)) - ep(n%3)  ) * (n^3)  )
That would be easier to read.
2*(1 - 0.01n)*(n3)
= int( 2n3 - 0.02n4 )
(  1 - ((n - 50)*0.01)  ) * (n^3)
= int( 1.5n3 - 0.01n4 )
(1.6 - 0.01n) * (n3)
= int( 1.6n3 - 0.01n4 )