User talk:IWannaBeTheVeryBest: Difference between revisions

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(→‎Multi-strike moves: new section)
(→‎Independent events: new section)
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Can you do the categories too please? Thanks for your help in getting the correct terminology in use. --[[User:SnorlaxMonster|<span style="color:#A70000">'''Snorlax'''</span>]][[User talk:SnorlaxMonster|<span style="color:#0000A7">'''Monster'''</span>]] 07:49, 9 September 2012 (UTC)
Can you do the categories too please? Thanks for your help in getting the correct terminology in use. --[[User:SnorlaxMonster|<span style="color:#A70000">'''Snorlax'''</span>]][[User talk:SnorlaxMonster|<span style="color:#0000A7">'''Monster'''</span>]] 07:49, 9 September 2012 (UTC)
== Independent events ==
Each hit of a multi-strike move is independently affected by the King's Rock/Razor Fang. Using your logic of (number of trials)*(probability of a single event)=(combined probability), if I were to flip two coins, there would be a 100% chance of flipping a heads, as there are 2 events and a 50% chance of heads in each trial. This is explained in further detail on Wikipedia: {{wp|Independence (probability theory)}}. The actual probability is 75% chance of heads:
:<code>Pr(H<sub>1</sub>∩H<sub>2</sub>)=Pr(H<sub>1</sub>)+Pr(H<sub>2</sub>)-Pr(H<sub>1</sub>∪H<sub>2</sub>)</code>
:<code>Pr(H<sub>1</sub>∩H<sub>2</sub>)=Pr(H<sub>1</sub>)+Pr(H<sub>2</sub>)-(Pr(H<sub>1</sub>)×Pr(H<sub>2</sub>))</code>
:<code>Pr(H<sub>1</sub>∩H<sub>2</sub>)=0.5+0.5-(0.5×0.5)</code>
:<code>Pr(H<sub>1</sub>∩H<sub>2</sub>)=0.75</code> --[[User:SnorlaxMonster|<span style="color:#A70000">'''Snorlax'''</span>]][[User talk:SnorlaxMonster|<span style="color:#0000A7">'''Monster'''</span>]] 06:48, 12 September 2012 (UTC)

Revision as of 06:48, 12 September 2012

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Scizor and Scissor

I don't think that would be notable considering the similar pronunciation between the two.--ForceFire 12:08, 7 May 2012 (UTC)

Multi-strike moves

Can you do the categories too please? Thanks for your help in getting the correct terminology in use. --SnorlaxMonster 07:49, 9 September 2012 (UTC)

Independent events

Each hit of a multi-strike move is independently affected by the King's Rock/Razor Fang. Using your logic of (number of trials)*(probability of a single event)=(combined probability), if I were to flip two coins, there would be a 100% chance of flipping a heads, as there are 2 events and a 50% chance of heads in each trial. This is explained in further detail on Wikipedia: Independence (probability theory). The actual probability is 75% chance of heads:

Pr(H1∩H2)=Pr(H1)+Pr(H2)-Pr(H1∪H2)
Pr(H1∩H2)=Pr(H1)+Pr(H2)-(Pr(H1)×Pr(H2))
Pr(H1∩H2)=0.5+0.5-(0.5×0.5)
Pr(H1∩H2)=0.75 --SnorlaxMonster 06:48, 12 September 2012 (UTC)